Date: Tue, 3 Nov 1998 16:08:35 -0500 From: Kozick Rich To: stevensn@bucknell.edu, mayega@bucknell.edu, witherup@bucknell.edu, venrchck@bucknell.edu, sgunnels@bucknell.edu, senator@bucknell.edu, bjgreen@bucknell.edu, rhess@bucknell.edu, hathaway@bucknell.edu, baxter@bucknell.edu, karavanc@bucknell.edu, coviello@bucknell.edu, jbullard@bucknell.edu, daub@bucknell.edu, harkness@bucknell.edu, cwlay@bucknell.edu, armentrt@bucknell.edu, barthel@bucknell.edu, cwil@bucknell.edu, goossen@bucknell.edu, rrusso@bucknell.edu, webb@bucknell.edu, bpitzer@bucknell.edu, everitt@bucknell.edu, rudis@bucknell.edu, gratz@bucknell.edu, afgibson@bucknell.edu, onybrchi@bucknell.edu, diamond@bucknell.edu, mzeigler@bucknell.edu, lundgren@bucknell.edu, pickert@bucknell.edu, reed@bucknell.edu, ryoung@bucknell.edu, franclno@bucknell.edu, yyoon@bucknell.edu, phan@bucknell.edu, kozick@bucknell.edu Subject: HW 16 note Hi, Problem 4 on homework 16 may be simpler if you multiply the sinc function by 2000. In other words, you can take X(omega) to be: X(omega) = 2000 sinc (1000 omega / pi) Then x(t) is easier to find using the Fourier transform table. (We will learn in class how to solve the original problem 4 on the homework 16 sheet.) Thanks. -- Rich Kozick